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Re[2]: Sfericheskaya astronomiya
3.03.2012 16:44 | G. B. Vishnyackii
Citata: |
Orty sfericheskoi sistemy koordinat vyrazhayutsya cherez orty dekart ovoi sleduyushim obrazom: ir = (cos(la mbda)*ix+ sin(lambda)*iy)sin(theta) + cos(the ta)*iz, ilambda = -sin(lamb da)*ix+ cos(lambda)*iy, itheta = (co s(lambda)*ix+ sin(lambda)*iy)cos(theta)- s in(theta)*iz, otkuda, pri theta=90o i l ambda=0o sleduet, chto ir = < strong>ix, ilambda = < strong>iy, itheta = -iz. Eto oznachaet, chto troiki ortonormirovannogo bazisa dek artovoi i sfe richeskoi sistem koordinat - protivopolozhno orientirovany (znak "-" pered ortom iz). Esliu dekartovoi sistemypravaya orientaciya bazisno i troiki, to u sistemy sfericheskoi v dannom sluchae ona - LEVAYa. Avtoram stat'i neobhod imo razobrat'sya s putanicei, vytekayushei iz togo, chto oni pishut. Nu i chto? Bednya ga.... |
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