V. Sh. Yanbikov
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Volnovaya model' gravitacii
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2.11.2016 17:47 |
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Volnovaya model' gravitacii
Avtor: Yanbikov Vil'dyan Shavkyatovich, g. Volgograd
Annotaciya: Postroena fenomenologicheskaya volnovaya model' gravitacionnogo
vzaimodeistviya veshestva kosmosa. Poluchena formula gravitacionnogo vzaimodeistviya
mezhdu tyagoteyushimi massami. Poluchena formula gravitacionnogo prityazheniya mezhdu
protonami na ochen' blizkom rasstoyanii mezhdu nimi.
Pust' dva protona nahodyatsya na rasstoyanii R drug ot druga i nepodvizhny
otnositel'no absolyutnogo kosmicheskogo prostranstva (ris.1). Pri etom veshestvo
Vselennoi razdrobleno na protony. Protony Vselennoi nahodyatsya v sostoyanii
svobodnogo padeniya, chto yavlyaetsya idealizaciei real'nogo sostoyaniya veshestva vo
Vselennoi. Rassmotrim volnovuyu model' gravitacionnogo vzaimodeistviya mezhdu
nepodvizhnymi protonami. Oboznachim eti protony kak A i V (ris.1). Na protony A i V
so vseh storon v predelah telesnogo ugla 4π padayut volny vysokochastotnogo
gravitacionnogo polya ot veshestva beskonechnogo kosmicheskogo prostranstva. V moei
issledovatel'skoi rabote po ekranirovaniyu gravitacii v kosmose bylo polucheno
vyrazhenie dlya napryazhennosti gravitacionnogo polya ot beskonechnogo kosmicheskogo poluprostranstva
g = 3/2 γ πm/σ ; gde γ gravitacionnaya postoyannaya, π = 3.14 , m - massa pokoya
protona, σ sechenie ekranirovaniya vysokochastotnyh voln gravitacii protonom nahodyashemsya v
svobodnom padenii v kosmicheskom prostranstve. Primem σ = πdd/4 ; gde
d = 3*10 15 m diametr protona. Padayushie iz kosmosa VCh gravitacionnye volny
nakachivayut protony A i V gravitacionnoi energiei. Dlya sohraneniya energeticheskogo
balansa, protony A i V izluchayut izbytochnuyu energiyu v kosmicheskoe prostranstvo v
predelah telesnogo ugla 4π v vide sfericheski simmetrichnyh gravitacionnyh volnovyh
frontov. Eti volnovye fronty, pri padenii na protony kosmosa, okazyvayut silovoe
vozdeistvie na eti protony. Rassmotrim silovoe vzaimodeistvie mezhdu protonami A i
V. Pust' v nekotoryi moment vremeni proton A izluchil sfericheski simmetrichnyi
volnovoi front s energiei ε0 . Cherez nekotoroe vremya etot volnovoi front dostignet
protona V. Chast' energii etogo volnovogo fronta budet pogloshena protonom V.
Oboznachim etu energiyu kak ε2 . Togda ε2 = ( ε0πrr)/4πRR = ε0/4 rr/RR ; gde r = d/2
radius protona.
Posle poglosheniya protonom V energii ε2 , proton V izluchaet volnovoi front s energiei
ε0 + ε2 Cherez nekotoroe vremya etot volnovoi front dostignet protona A. Chast' energii
etogo volnovogo fronta budet pogloshena protonom A . Oboznachim etu energiyu
ε1 = ((ε0 + ε2))/4πRR πr2 = ε0/4 (1+rr/4RR ) rr/RR
V etot zhe moment vremeni proton A izluchaet volnovoi front s energiei ε0 + ε1 Cherez
nekotoroe vremya etot volnovoi front dostignet protona V. Chast' energii etogo fronta
budet pogloshena protonom V. Oboznachim etu energiyu
ε22 = ((ε0 + ε1))/4πRR πr2 = ε0/4 ( 1+ rr/4RR + rrrr/16RRRR ) rr/RR V tot zhe moment proton
V izluchit
volnovoi front s energiei ε0 + ε22 . Cherez nekotoroe vremya etot volnovoi front
dostignet protona A . Oboznachim energiyu pogloshennuyu protonom A kak
ε11 = ((ε0 + ε22))/4πRR πr2 = ε0/4 ( 1+ rr/4RR + rrrr/16RRRR+rrrrrr/64RRRRRR ) rr/RR V
etot zhe moment
proton A izluchit volnovoi front s energiei ε0 + ε11 Cherez nekotoroe vremya etot
volnovoi front dostignet protona V . Energiya pogloshennaya protonom V budet ravna
ε222 = ((ε0 + ε11))/4πRR πr2 Process izlucheniya i poglosheniya budet proishodit' beskonechnoe
chislo raz. Pri etom energiya iz kosmosa pogloshaetsya protonami A i V nepreryvno i
postoyanno vo vremeni. Dlya energii εnnn... vyrazhenie v skobkah est' geometricheskaya
progressiya, summa kotoroi ravna S = 1/(1-rr/4RR) Dlya R >> r summa S ≈ 1 Ochevidno energiya
ε0 proporcional'na napryazhennosti 2g =3 γ πm/σ Ili ε0 = 3kπγ m/σ
gde k koefficient proporcional'nosti. Naidem vyrazhenie dlya zakona vsemirnogo
tyagoteniya. Energiya obmena mezhdu protonami ε = ε0/4 rr/RR proporcional'na gp , gde gp
napryazhennost' gravitacionnogo polya vozdeistvuyushego na proton A so storony protona
V. Togda ε0 = 2kg i ε = k gp Otsyuda ε/ε0 = gp/2g = rr/4RR
Otsyuda gp = 1/(2 ) g rr/RR = 3/4 πγ m/σ rr/RR Ili gp = 3/4 γ m/RR
Okonchatel'no sila vzaimodeistviya mezhdu protonami F = m gp = 3/4 γ mm/RR ; gde 3/4 γ est'
koefficient gravitacii. V privedennom issledovanii 3/4 γ < γ . Eto ob'yasnyaetsya tem,
chto v real'nosti v kosmose sushestvuyut sgustki veshestva v vide zvezd, planet,
asteroidov prakticheski bez poter' pereizluchayushih gravitacionnuyu energiyu obratno v
kosmos. Po etoi prichine vnutri solnechnoi sistemy plotnost' gravitacionnoi energii
neskol'ko vyshe chem v modeli, v kotoroi veshestvo razdrobleno do protonov. Protonnyi
gaz ne tol'ko pereizluchaet, no i chastichno pogloshaet gravitacionnuyu energiyu, rashoduya
ee na kineticheskuyu energiyu svoego dvizheniya. V modeli protonnogo gaza plotnost'
gravitacionnoi energii men'she chem vnutri solnechnoi sistemy, a eto oznachaet chto
3/4 γ < γ Vozmozhno ne uchityvaetsya nakachka gravitacionnoi energiei elektromagnitnym
izlucheniem kosmosa.
http://astrogalaxy.ru/forum/phpBB2/viewforum.php?f=11
http://www.astronomy.ru/forum/index.php/board,2.0.html
http://forum.lebedev.ru/viewforum.php?f=12
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