![Na pervuyu stranicu](http://images.astronet.ru/img/bookicon.gif)
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4.5 Ustoichivost' teplovogo potoka
Rassmotrim prostuyu zadachu. Pust' imeyutsya dve plastiny s zadannymi temperaturami
i
, veshestvo mezhdu nimi s teploprovodnost'yu
, zavisyashei ot
(sm.
ris. 22).
V stacionarnyh usloviyah ustanovitsya potok tipa
![$\displaystyle H=-D{dT\over dx}.
$](https://images.astronet.ru/pubd/2008/02/15/0001226214/img919.gif)
![$ D$](https://images.astronet.ru/pubd/2008/02/15/0001226214/img918.gif)
![$ H$](https://images.astronet.ru/pubd/2008/02/15/0001226214/img342.gif)
Otvet ``'' neveren. V stacionarnoi kartine
const
![$\displaystyle H={\int\limits_{T_1}^{T_2}DdT\over {x_1-x_2}}.
$](https://images.astronet.ru/pubd/2008/02/15/0001226214/img922.gif)
Poetomu, esli pri nekotoryh temperaturah (tochnee, ochen' malo), to nemnogo
umen'shitsya
sootvetstvenno upadet, no ne obratitsya v nul'.
Vazhno, chto
podstroitsya tak, chto
const, poyavitsya skachok
(sm. ris. 23).
Drugoe delo, esli zadat'
kak funkciyu
; v etom sluchae potok
mog by i obratit'sya v nul', tak kak v etom sluchae
![$\displaystyle H={{T_1-T_2}\over \int {1\over D}\,dx},
$](https://images.astronet.ru/pubd/2008/02/15/0001226214/img926.gif)
![$ D\to 0$](https://images.astronet.ru/pubd/2008/02/15/0001226214/img927.gif)
![$ H\to 0$](https://images.astronet.ru/pubd/2008/02/15/0001226214/img928.gif)
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