Topologiya i metrika par keplerovskih orbit
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4. Estestvennye metriki v prostranstve keplerovskih orbit
Budem teper' schitat' tochkoi v pyatimernom prostranstve
keplerovskih ellipsov. Postroim neskol'ko estestvennyh metrik
v
. Malost'
oznachaet, chto orbity
pochti sovpadayut.
Dlya postroeniya rasstoyaniya predstavlyaetsya estestvennym sravnivat' tochki s odinakovoi ekscentricheskoi anomaliei. Takim putem poluchaem ravnomernuyu i srednekvadraticheskuyu metriki
Naibol'shee znachenie i integral berutsya po otrezku
![](https://images.astronet.ru/pubd/2002/05/12/0001176736/img135.gif)
Legko dokazat', chto vse aksiomy metricheskogo prostranstva vypolneny
dlya obeih metrik (10), (11), esli isklyuchit' krugovye
orbity. Inymi slovami, rasstoyaniya (10), (11) opredeleny i
topologicheski ekvivalentny v prostranstve nekrugovyh
ellipticheskih orbit. Oni razryvny v okrestnosti hotya by odnoi
krugovoi orbity iz pary. Prichina ochevidna. Naprimer, dve komplanarnye
orbity s odinakovoi bol'shoi poluos'yu i pochti nulevymi
ekscentrisitetami pochti sovpadayut nezavisimo ot napravleniya apsid. No
oba rasstoyaniya sushestvenno zavisyat ot ih napravleniya.
Chtoby izbezhat' nepriyatnostei, my dolzhny sravnivat' tochki, imeyushie razlichnye vzaimnye polozheniya. Horoshii sposob - vvesti sleduyushie metriki:
Naibol'shee znachenie i integral berutsya po otrezku
![](https://images.astronet.ru/pubd/2002/05/12/0001176736/img135.gif)
![](https://images.astronet.ru/pubd/2002/05/12/0001176736/img139.gif)
Vse aksiomy metricheskogo prostranstva vypolneny
dlya obeih metrik (12), (13) vo vsem prostranstve ,
hotya dokazatel'stvo mnogo slozhnee, chem v predydushem sluchae.
Rasstoyaniya (12), (13) topologicheski ekvivalentny i prevrashayut
v otkrytoe, neogranichennoe, lokal'no-kompaktnoe metricheskoe
prostranstvo.
Privedem algoritmy opredeleniya rasstoyanii .
1. Oboznachim
. Ochevidno,
gde
![](https://images.astronet.ru/pubd/2002/05/12/0001176736/img143.gif)
![](https://images.astronet.ru/pubd/2002/05/12/0001176736/img144.gif)
![](https://images.astronet.ru/pubd/2002/05/12/0001176736/img145.gif)
Pervyi shag sostoit v nahozhdenii vseh veshestvennyh, lezhashih na
okruzhnosti kornei uravneniya
gde
![](https://images.astronet.ru/pubd/2002/05/12/0001176736/img147.gif)
![](https://images.astronet.ru/pubd/2002/05/12/0001176736/img148.gif)
![](https://images.astronet.ru/pubd/2002/05/12/0001176736/img149.gif)
2. Integral (11) elementaren. Dlya vtorogo rasstoyaniya poluchaem prostuyu formulu
3. Algoritm vychisleniya tret'ego rasstoyaniya stol' slozhen,
chto my ne rekomenduem ispol'zovat' na praktike.
4. Integral v (13) elementaren
![](https://images.astronet.ru/pubd/2002/05/12/0001176736/img153.gif)
![](https://images.astronet.ru/pubd/2002/05/12/0001176736/img154.gif)
![](https://images.astronet.ru/pubd/2002/05/12/0001176736/img155.gif)
![](https://images.astronet.ru/pubd/2002/05/12/0001176736/img156.gif)
<< 3. Topologiya par orbit | Oglavlenie | 5. Pochti peresekayushiesya orbity >>
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